Working on my own image host --

[Ryan]

So lately I've been working on my own image host in PHP/Perl. The image handler and everything else is PERL and the file upload (WIP) is in PHP.

Right now it appears that my images for some reason are having difficulty caching for some people, is this image caching for everyone?



(yeah, it's a random image I found on 4chan, just ignore =p)

[Bennett 🚀]

As long as you're not serving the images via PHP or Perl, there shouldn't be any cache problems.

[Ryan]

Aug 22, 2012 15:43:28 GMT -8 Bennett 🚀 said:

As long as you're not serving the images via PHP or Perl, there shouldn't be any cache problems.

They are being served via a perl script I wrote, the appear to be caching.

[Bennett 🚀]

Well, however you're using Perl to display the image, make sure it has the headers of an image along with the cache-expiration.

[Ryan]

Aug 22, 2012 16:26:11 GMT -8 Bennett 🚀 said:

Well, however you're using Perl to display the image, make sure it has the headers of an image along with the cache-expiration.

Yeah, I've since added that after making this thread.

$zhr=time2str("%a, %d %b %Y %X %Z", time);
$thr=time2str("%a, %d %b %Y %X %Z", time+86400);
print "Date: ".$zhr."\n";
print "Expires:".$thr."\n";

[Bennett 🚀]

Aug 22, 2012 16:27:38 GMT -8 Ryan said:

Aug 22, 2012 16:26:11 GMT -8 Bennett 🚀 said:

Well, however you're using Perl to display the image, make sure it has the headers of an image along with the cache-expiration.

Yeah, I've since added that after making this thread.

$zhr=time2str("%a, %d %b %Y %X %Z", time);
$thr=time2str("%a, %d %b %Y %X %Z", time+86400);
print "Date: ".$zhr."\n";
print "Expires:".$thr."\n";

$zhr=time2str("%a, %d %b %Y %X %Z", time);
$thr=time2str("%a, %d %b %Y %X %Z", time+86400);

Why is "time" without a $ in the time2str function's parameters? Or is this perl but looks like PHP? Dx

[Ryan]

Aug 22, 2012 16:31:31 GMT -8 Bennett 🚀 said:

Aug 22, 2012 16:27:38 GMT -8 Ryan said:

Yeah, I've since added that after making this thread.

$zhr=time2str("%a, %d %b %Y %X %Z", time);
$thr=time2str("%a, %d %b %Y %X %Z", time+86400);
print "Date: ".$zhr."\n";
print "Expires:".$thr."\n";

$zhr=time2str("%a, %d %b %Y %X %Z", time);
$thr=time2str("%a, %d %b %Y %X %Z", time+86400);

Why is "time" without a $ in the time2str function's parameters? Or is this perl but looks like PHP? Dx

Haha it's perl, also they're in vars since I have those two stored in different blocks, the time functions are defined with the rest of my vars.